NECO 2009 Chemistry · Question 39

If the volume of a gas at 35°C is 60cm3, what would be its volume in cm3 at 273k?

Options

  1. A.39.03
  2. B.46.81
  3. C.53.18
  4. D.67.69
  5. E.76.92

Answer: C. 53.18

Explanation written with AI and checked against the answer key

Analyze the question: A gas has a volume of 60 cm³ at 35°C. We need its volume at 273 K, and the pressure is assumed constant. This is a Charles' Law problem.

Concept: Charles' Law says that at constant pressure, volume is directly proportional to absolute temperature (in kelvin):

V₁/T₁ = V₂/T₂

Solution:

  1. Convert the temperature to kelvin: T₁ = 35 + 273 = 308 K T₂ = 273 K
  1. Substitute the values: V₂ = V₁ × (T₂/T₁) V₂ = 60 × (273/308)
  1. Calculate: 273/308 = 0.88636 V₂ = 60 × 0.88636 ≈ 53.18 cm³

Check against the options: 53.18 matches option C.

Answer: The volume at 273 K is about 53.18 cm³, which is option C.

Tip: Always convert °C to K before using gas laws. When the gas is cooled, the volume must decrease, so your answer should be smaller than 60. That rules out D and E immediately. Also remember that 273 K is 0°C, so this is a cooling from 35°C to 0°C.

AI can make mistakes. Report anything that looks wrong.

Past questions © the examination body (JAMB/WAEC/NECO). DeeepSolve is not affiliated with them. Rights holders: see /copyright.