NECO 2001 Chemistry · Question 39
On exposure to hydrogen sulphide, moist lead (II) ethanoate paper turns
Options
- A.black
- B.blue
- C.green
- D.white
- E.yellow
Answer: A. black
Explanation written with AI and checked against the answer key
Analyze the question: This is a test for hydrogen sulphide (H₂S) gas. Moist lead(II) ethanoate (lead acetate) paper is the standard test paper used to detect it.
Concept: H₂S reacts with soluble lead(II) salts to form lead(II) sulphide (PbS). PbS is an insoluble black solid. This is why the test paper changes colour.
Solution:
Pb(CH₃COO)₂ (aq) + H₂S (g) → PbS (s) + 2CH₃COOH (aq)
- Lead(II) ethanoate paper is originally white.
- When it meets H₂S, black lead(II) sulphide forms on the paper.
- The paper therefore turns black (sometimes described as silvery-black or brownish-black).
Checking the other options:
- Blue: this is typical of copper(II) compounds or of litmus in alkalis, not of PbS.
- Green: this is associated with Fe²⁺ or Cu²⁺ salts, not with this test.
- White: this is the colour of the paper before the test, so no reaction is shown.
- Yellow: PbS is not yellow. Lead(II) iodide and lead(II) chromate are yellow.
Answer: A. black.
Exam tip: Remember "lead + sulphide = black". Lead(II) ethanoate paper detects H₂S by turning black. In contrast, acidified potassium dichromate(VI) turns from orange to green with SO₂, so don't mix up the two gas tests.
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