NECO 2001 Chemistry · Question 21
Faraday s first law of electrolysis can be expressed mathematically as
Options
- A.m=I/it
- B.mαit
- C.Q=it
- D.QαI/it
- E.Qαit
Answer: B. mαit
Explanation written with AI and checked against the answer key
Analyze the question: Faraday's first law of electrolysis relates the mass of a substance deposited or liberated at an electrode to the quantity of electricity passed through the electrolyte.
Concept: The law says that the mass (m) of a substance liberated during electrolysis is directly proportional to the quantity of electricity (Q) passed:
m ∝ Q
Quantity of electricity is current multiplied by time:
Q = I × t
Substituting this into the proportionality gives:
m ∝ It
This can also be written as m = ZIt, where Z is the electrochemical equivalent of the substance.
Checking the options:
- A. m = I/it is wrong. It is dimensionally meaningless and is not Faraday's law.
- B. m ∝ it is correct. It is the mathematical statement of the first law.
- C. Q = it is a true relationship, but it only defines charge. It does not involve mass, so it is not the law.
- D. Q ∝ I/it is wrong.
- E. Q ∝ it is true, but it is trivial because Q = It by definition. It does not state the law, since mass is missing.
Answer: B. The first law links mass to the current and time, m ∝ It.
Exam tip: Faraday's first law is always about mass (m) and quantity of electricity (Q = It). If an option has m ∝ Q or m ∝ It, choose it. Options without m, like C and E, only describe charge.
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