JAMB 2025 Physics · Question 101

The power of a lens in diopters is

Options

  1. A.3f
  2. B.1f\frac{1}{\text{f}}
  3. C.2f
  4. D.f

Answer: B. 1f\frac{1}{\text{f}}

Explanation written with AI and checked against the answer key

Analysis

The question asks for the mathematical definition of the power of a lens, specifically when measured in diopters.

Concept

In optics, the power of a lens (PP) is a measure of its ability to converge or diverge light rays. It is defined as the reciprocal of the focal length (ff) of the lens, provided that the focal length is measured in meters.

The unit of power is the diopter (D), where 1 diopter=1 m−11 \text{ diopter} = 1 \text{ m}^{-1}.

The formula is expressed as:

P=1f(in meters)P = \frac{1}{f(\text{in meters})}
Solution
  1. Identify the relationship: The power of a lens is inversely proportional to its focal length.
  2. Apply the unit constraint: For the power to be expressed in diopters, the focal length ff must be in meters.
  3. Formulate the equation: P=1fP = \frac{1}{f}.
  4. Compare with the given options: • Option A: 3f3f (Incorrect) • Option B: 1f\frac{1}{f} (Correct) • Option C: 2f2f (Incorrect) • Option D: ff (Incorrect)
Exam Tip

Always check the units! If a JAMB question gives you the focal length in centimeters (cm), you must convert it to meters (m) by dividing by 100 before using the formula P=1fP = \frac{1}{f}. For example, if f=20 cmf = 20\text{ cm}, convert it to 0.2 m0.2\text{ m}, then P=10.2=5 dioptersP = \frac{1}{0.2} = 5\text{ diopters}.

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