JAMB 2025 Physics · Question 75

If the weight of an object on the Earth's surface is 2.5 x 10 ^3 N, what is its weight on the moon's surface…

Question

If the weight of an object on the Earth's surface is 2.5 x 103^3N, what is its weight on the moon's surface if the gravitational force of the moon is one-sixth of the Earth's(g = 10m/s−2^{-2})

  1. A.360.87N
  2. B.416.67N
  3. C.214.49N
  4. D.510.79N

Answer: B. 416.67N

Explanation written with AI and checked against the answer key

Analysis

The question asks us to calculate the weight of an object on the Moon, given its weight on Earth and the relationship between the gravitational pull of the Moon and the Earth.

Concept

Weight (WW) is the force of gravity acting on an object's mass (mm). It is calculated using the formula: W=mgW = mg where gg is the acceleration due to gravity.

Since the mass (mm) of an object remains constant regardless of its location, the weight of an object on the Moon (WmW_m) is directly proportional to the gravitational acceleration on the Moon (gmg_m). Given that gm=16geg_m = \frac{1}{6} g_e (where geg_e is gravity on Earth), it follows that: Wm=16WeW_m = \frac{1}{6} W_e

Solution
  1. Identify the given values: • Weight on Earth (WeW_e) = 2.5×103 N=2500 N2.5 \times 10^3\text{ N} = 2500\text{ N} • Gravitational relationship: gm=16geg_m = \frac{1}{6} g_e
  1. Apply the formula: Wm=We6W_m = \frac{W_e}{6} Wm=25006W_m = \frac{2500}{6}
  1. Calculate the result: Wm=416.666... NW_m = 416.666... \text{ N} Rounding to two decimal places, we get 416.67 N.
Conclusion

Comparing our result to the provided options, the correct value is 416.67 N.

Exam Tip

Always remember that mass is a scalar quantity that stays the same everywhere in the universe, while weight is a vector quantity (a force) that changes depending on the gravitational field strength of the location. If a question asks for mass, ensure you divide the weight by gg (10 m/s210\text{ m/s}^2) first!

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