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JAMB 2024 Physics · Question 7

The distance between two successive crests of a water wave is 0.25m. If a particle on the surface of the water…

Question

The distance between two successive crests of a water wave is 0.25m. If a particle on the surface of the water makes four complete vertical oscillations in one second. Calculate the speed of the wave.

  1. A.4ms−1^{-1}
  2. B.3ms−1^{-1}
  3. C.2ms−1^{-1}
  4. D.1ms−1^{-1}

Answer: D. 1ms−1^{-1}

Explanation written with AI and checked against the answer key

Analyze the question

  • Distance between two successive crests = wavelength, λ = 0.25 m
  • Four complete oscillations in one second means frequency, f = 4 Hz
  • We need the wave speed, v

Concept The wave equation links speed, frequency and wavelength:

v = fλ

Solution v = 4 × 0.25 = 1 m/s

Answer: The speed of the wave is 1 ms⁻¹.

Tip: In wave questions, "distance between successive crests (or troughs)" always means wavelength. "Number of oscillations per second" always means frequency. Then just multiply: v = fλ.

AI can make mistakes. Report anything that looks wrong.

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