An air force jet flying with a speed of 335m/s went past an anti-aircraft gun. How far is the aircraft 5s later when the gun was fired?

1. Analyze the question

We are given the speed of an aircraft ($v = 335 \, \text{m/s}$) and the time elapsed ($t = 5 \, \text{s}$). We need to calculate the distance ($d$) the aircraft has traveled from the point where it passed the gun to its position when the gun was fired.

2. Explain the concept

This is a classic problem involving Uniform Linear Motion. Since the jet is flying at a constant speed, we use the basic formula for distance:

3. Show the solution

• Step 1: Identify the given values • Speed ($v$) = $335 \, \text{m/s}$ • Time ($t$) = $5 \, \text{s}$

• Step 2: Apply the formula • $d = 335 \, \text{m/s} \times 5 \, \text{s}$

• Step 3: Calculate the result • $335 \times 5 = 1675$ • $d = 1675 \, \text{m}$

4. Identify the answer

Comparing our result to the given options: A. 838m B. 1675m C. 670m D. 3350m

The calculated distance is 1675m, which corresponds to option B.

5. Exam Tip

When solving motion problems in JAMB, always check your units first. If the speed were in km/h, you would need to convert it to m/s (by multiplying by $5/18$) before multiplying by time in seconds. In this case, the units were already consistent, making the calculation straightforward!