JAMB 2024 Physics · Question 118

A refrigerator uses 150W. If it is kept on for 336 hours non-stop, what is the energy consumed in KWh?

Options

  1. A.60.20KWh
  2. B.50.40KWh
  3. C.25.01KWh
  4. D.30.20KWh

Answer: B. 50.40KWh

Explanation written with AI and checked against the answer key

1. Analyze the question

We are given the power rating of a refrigerator in Watts (W) and the time it runs in hours (h). We need to calculate the total energy consumed and express it in Kilowatt-hours (KWh).

2. Explain the concept

Energy (EE) is defined as the product of Power (PP) and Time (tt):

E=P×tE = P \times t

To get the answer in KWh, we must ensure:

  • Power is in Kilowatts (KW). To convert Watts to Kilowatts, divide by 1,000.
  • Time is in hours (h).
3. Show the solution

Step 1: Convert Power from Watts to Kilowatts

P=150 WP = 150\text{ W}
P(in KW)=1501000=0.15 KWP (\text{in KW}) = \frac{150}{1000} = 0.15\text{ KW}

Step 2: Identify the Time

t=336 hourst = 336\text{ hours}

Step 3: Calculate Energy

E=P×tE = P \times t
E=0.15 KW×336 hE = 0.15\text{ KW} \times 336\text{ h}
E=50.4 KWhE = 50.4\text{ KWh}
4. Identify the answer

Comparing our result (50.4 KWh50.4\text{ KWh}) to the given options, it matches option B.

5. Exam Tip

Always check the units requested in the question! If the question asks for KWh, convert your power to KW first. If it asks for Joules, ensure your power is in Watts and your time is in seconds (E=P×tE = P \times t).

AI can make mistakes. Report anything that looks wrong.

Past questions © the examination body (JAMB/WAEC/NECO). DeeepSolve is not affiliated with them. Rights holders: see /copyright.