JAMB 2024 Physics · Question 23

A particular household utilizes three electrical appliances for six hours daily if the appliances are rated…

Question

A particular household utilizes three electrical appliances for six hours daily if the appliances are rated 80W, 100W, and 120W respectively. Calculate the electrical bills paid monthly if an average month is 31 days. [1kwh = #24.08k]

  1. A.₦ 2843.22k
  2. B.₦ 1950.22k
  3. C.₦ 1343.66k
  4. D.₦ 46.23k

Answer: C. ₦ 1343.66k

Explanation written with AI and checked against the answer key

Analyze the question: Three appliances (80 W, 100 W, 120 W) each run 6 hours daily for 31 days. The energy cost is ₦24.08 per kWh. We need the monthly bill.

Concept: Energy (kWh) = Power (kW) × Time (hours) Cost = Energy × Rate

Solution:

  1. Total power = 80 + 100 + 120 = 300 W = 0.3 kW
  1. Energy used per day = 0.3 kW × 6 h = 1.8 kWh
  1. Energy used in 31 days = 1.8 × 31 = 55.8 kWh
  1. Cost = 55.8 × ₦24.08 = ₦1343.664 ≈ ₦1343.66k

Check: 55.8 × 24 = 1339.2 and 55.8 × 0.08 = 4.464, so the total is 1343.664. ✓

Tip: In electricity-bill questions, always follow this chain: add the powers → convert W to kW (divide by 1000) → multiply by hours → multiply by days → multiply by the cost per kWh. Most mistakes come from forgetting to convert watts to kilowatts. Option D (₦46.23k) is the kind of wrong answer you'd get from a slip in the conversion or in the number of days.

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