JAMB 2022 Physics · Question 14

A car starts from rest and covers a distance of 40 m in 10 s. Calculate the magnitude of its acceleration

Options

  1. A.3.20 ms−2^{-2}
  2. B.0.25 ms−2^{-2}
  3. C.0.80 ms−2^{-2}
  4. D.4.00 ms−2^{-2}

Answer: C. 0.80 ms−2^{-2}

Explanation written with AI and checked against the answer key

1. Analyze the Question

We are given the following information about a car's motion:

  • Initial velocity (uu) = 0 ms−10 \text{ ms}^{-1} (since it starts from rest)
  • Distance covered (ss) = 40 m40 \text{ m}
  • Time taken (tt) = 10 s10 \text{ s}
  • We need to find the acceleration (aa).
2. Explain the Concept

To solve this, we use the equations of uniformly accelerated motion. Specifically, the second equation of motion relates distance, initial velocity, time, and acceleration:

s=ut+12at2s = ut + \frac{1}{2}at^2

Where:

  • ss is the distance
  • uu is the initial velocity
  • tt is the time
  • aa is the acceleration
3. Show the Solution

Step 1: Substitute the known values into the formula.

40=(0×10)+12×a×(10)240 = (0 \times 10) + \frac{1}{2} \times a \times (10)^2

Step 2: Simplify the equation. Since 0×10=00 \times 10 = 0:

40=0+12×a×10040 = 0 + \frac{1}{2} \times a \times 100
40=50a40 = 50a

Step 3: Solve for aa.

a=4050a = \frac{40}{50}
a=0.8 ms−2a = 0.8 \text{ ms}^{-2}
4. Identify the Answer

Comparing our result to the given options: A. 3.20 ms−2^{-2} B. 0.25 ms−2^{-2} C. 0.80 ms−2^{-2} D. 4.00 ms−2^{-2}

The calculated value matches Option C.

5. Exam Tip

Whenever you see the phrase "starts from rest," immediately note that u=0u = 0. This simplifies your equations significantly because the utut term disappears, leaving you with just s=12at2s = \frac{1}{2}at^2. This is a common shortcut in JAMB Physics to save you time!

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