JAMB 2018 Physics · Question 46

The linear expansivity of brass is 2 x 10−5^{-5} C−1^{-1}. If the volume of a piece of brass is 15.00cm at 0°C, what is the volume at 100°C

Options

  1. A.16.03cm3^3
  2. B.15.09cm3^3
  3. C.16.00cm3^3
  4. D.15.03cm3^3

Answer: B. 15.09cm3^3

Explanation written with AI and checked against the answer key

1. Analyze the Question

We are given the linear expansivity (α\alpha) of brass and its initial volume (V0V_0) at an initial temperature (θ1\theta_1). We need to find the final volume (V2V_2) after the temperature increases to θ2\theta_2.

Given data:

  • Linear expansivity (α\alpha) = 2×10−5 ∘C−12 \times 10^{-5} \, ^\circ\text{C}^{-1}
  • Initial volume (V0V_0) = 15.00 cm315.00 \, \text{cm}^3
  • Initial temperature (θ1\theta_1) = 0 ∘C0 \, ^\circ\text{C}
  • Final temperature (θ2\theta_2) = 100 ∘C100 \, ^\circ\text{C}
  • Change in temperature (Δθ\Delta\theta) = 100−0=100 ∘C100 - 0 = 100 \, ^\circ\text{C}
2. Explain the Concept

When a solid is heated, it expands in all directions. The relationship between linear expansivity (α\alpha) and cubic (volume) expansivity (γ\gamma) is given by:

γ=3α\gamma = 3\alpha

The formula for the change in volume (ΔV\Delta V) is:

ΔV=V0γΔθ\Delta V = V_0 \gamma \Delta\theta

Therefore, the final volume (V2V_2) is:

V2=V0(1+γΔθ)V_2 = V_0(1 + \gamma\Delta\theta)
3. Show the Solution

Step 1: Calculate the cubic expansivity (γ\gamma)

γ=3×α\gamma = 3 \times \alpha
γ=3×(2×10−5)=6×10−5 ∘C−1\gamma = 3 \times (2 \times 10^{-5}) = 6 \times 10^{-5} \, ^\circ\text{C}^{-1}

Step 2: Calculate the change in volume (ΔV\Delta V)

ΔV=V0×γ×Δθ\Delta V = V_0 \times \gamma \times \Delta\theta
ΔV=15.00×(6×10−5)×100\Delta V = 15.00 \times (6 \times 10^{-5}) \times 100
ΔV=15.00×6×10−3\Delta V = 15.00 \times 6 \times 10^{-3}
ΔV=90×10−3=0.09 cm3\Delta V = 90 \times 10^{-3} = 0.09 \, \text{cm}^3

Step 3: Calculate the final volume (V2V_2)

V2=V0+ΔVV_2 = V_0 + \Delta V
V2=15.00+0.09=15.09 cm3V_2 = 15.00 + 0.09 = 15.09 \, \text{cm}^3
4. Identify the Answer

Comparing our result (15.09 cm315.09 \, \text{cm}^3) to the given options, it matches option B.

5. Exam Tip

Always remember the "3" in γ=3α\gamma = 3\alpha. A common mistake students make is using the linear expansivity directly in the volume formula. Since volume is three-dimensional (length × breadth × height), you must multiply the linear expansivity by 3 to get the volume expansivity.

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