If a mango fruit dropped at a height of 50 meters. How long does it reach the ground? (take g = 10m/s2)

Analyze the question: A mango falls freely from rest through a height of 50 m. We need the time to reach the ground, with g = 10 m/s².

Concept: For free fall from rest (initial velocity u = 0), use the equation of motion:

h = ut + ½gt²

Since u = 0, this becomes:

h = ½gt², so t = √(2h/g)

Solution:

• h = 50 m, g = 10 m/s²
• t = √(2 × 50 / 10)
• t = √(100 / 10)
• t = √10
• t ≈ 3.16 s, which rounds to 3.2 s

Check against the options:

• A (2 s) would give h = ½(10)(4) = 20 m. Not 50 m.
• B (3 s) would give h = ½(10)(9) = 45 m. Close, but not 50 m.
• C (4 s) would give h = ½(10)(16) = 80 m. Too high.
• D (3.2 s) would give h = ½(10)(10.24) ≈ 51 m. This matches best.

Tip: For any "dropped from rest" question, go straight to t = √(2h/g). If the number under the root is not a perfect square, such as √10 here, expect a decimal answer. Remember that √9 = 3 and √16 = 4, so √10 sits just above 3, around 3.16. That quickly rules out the whole-number options. Also, always check your answer by substituting it back into h = ½gt².