JAMB 2015 Physics · Question 55

Convert 45°C to kelvin

Options

  1. A.318K
  2. B.250K
  3. C.184K
  4. D.120K

Answer: A. 318K

Explanation written with AI and checked against the answer key

Analysis

The question asks for the conversion of a temperature value from the Celsius scale (°C) to the Kelvin scale (K). This is a fundamental concept in thermodynamics often tested in JAMB Physics.

Concept

The relationship between the Celsius scale and the Kelvin scale is defined by the formula:

T(K)=θ(°C)+273.15T(K) = \theta(°C) + 273.15

In most JAMB and secondary school examinations, the value 273 is used as the standard constant for this conversion. Therefore, the simplified formula is:

T(K)=θ(°C)+273T(K) = \theta(°C) + 273
Solution
  1. Identify the given value: θ=45°C\theta = 45°C
  2. Apply the formula: T(K)=45+273T(K) = 45 + 273
  3. Perform the addition: 45+273=31845 + 273 = 318

So, 45°C is equivalent to 318K.

Conclusion

Comparing our result to the provided options: A. 318K B. 250K C. 184K D. 120K

The correct option is A.

Exam Tip

Always remember: "Celsius to Kelvin, add 273; Kelvin to Celsius, subtract 273." A common mistake students make is subtracting when they should be adding. Since the Kelvin scale starts at absolute zero (-273°C), the Kelvin value will almost always be higher than the Celsius value for temperatures above absolute zero.

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