JAMB 2014 Physics · Question 4

The equation PaVbTc= constant reduces to Charles Law if

Options

  1. A.a=1, b=1and c=0
  2. B.a=1, b=0 and c=-1
  3. C.a=0, b=1 and c=1
  4. D.a=0, b=1 and c=-1

Answer: D. a=0, b=1 and c=-1

Explanation written with AI and checked against the answer key

Analysis

The question asks us to identify the values of the exponents a,b,a, b, and cc in the general equation PaVbTc=constantP^a V^b T^c = \text{constant} that would transform it into Charles's Law.

Concept: Charles's Law

Charles's Law states that for a fixed mass of an ideal gas at constant pressure, the volume (VV) is directly proportional to its absolute temperature (TT).

Mathematically, this is expressed as:

VT=constant\frac{V}{T} = \text{constant}

Or, written in the form V⋅T−1=constantV \cdot T^{-1} = \text{constant}.

Step-by-Step Solution
  1. Compare the equations: We are given the general form: PaVbTc=constantP^a V^b T^c = \text{constant}. We want to reach the form: V1T−1=constantV^1 T^{-1} = \text{constant}.
  1. Match the variables: • To eliminate pressure (PP), the exponent aa must be 0 (since P0=1P^0 = 1). • To match the volume (VV), the exponent bb must be 1. • To match the temperature (TT), the exponent cc must be -1 (since T−1=1TT^{-1} = \frac{1}{T}).
  1. Verify: Substituting a=0,b=1,c=−1a=0, b=1, c=-1 into the original equation: P0⋅V1⋅T−1=constantP^0 \cdot V^1 \cdot T^{-1} = \text{constant} 1⋅V⋅1T=constant1 \cdot V \cdot \frac{1}{T} = \text{constant} VT=constant\frac{V}{T} = \text{constant} This matches the definition of Charles's Law perfectly.
Conclusion

Comparing our findings (a=0,b=1,c=−1a=0, b=1, c=-1) with the given options, we see that it corresponds to option D.

Exam Tip

When dealing with gas law equations in JAMB, remember the "Constant" rule:

  • Boyle’s Law: Temperature is constant (PV=kPV = k) →a=1,b=1,c=0\rightarrow a=1, b=1, c=0.
  • Charles’s Law: Pressure is constant (V/T=kV/T = k) →a=0,b=1,c=−1\rightarrow a=0, b=1, c=-1.
  • Pressure Law: Volume is constant (P/T=kP/T = k) →a=1,b=0,c=−1\rightarrow a=1, b=0, c=-1.

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