JAMB 2013 Physics · Question 1

A house has ten 40W and five 100W bulbs. How much will it cost the owner of the house to keep them lit for 10 hours if the cost of a unit is 5N?

Options

  1. A.N90
  2. B.N50
  3. C.N45
  4. D.N5

Answer: C. N45

Explanation written with AI and checked against the answer key

Analyze the question: We need the total energy used (in kWh, i.e. "units") and then multiply by the cost per unit.

Concept: Electrical energy = Power × Time. One unit = 1 kWh.

Solution:

  1. Power of the ten 40 W bulbs: 10 × 40 = 400 W
  2. Power of the five 100 W bulbs: 5 × 100 = 500 W
  3. Total power: 400 + 500 = 900 W = 0.9 kW
  4. Energy used in 10 hours: 0.9 kW × 10 h = 9 kWh (9 units)
  5. Cost: 9 × N5 = N45

Answer: Option C (N45).

Tip: Always convert watts to kilowatts before multiplying by hours. Then cost = kWh × price per unit. Option A (N90) is what you get if you double the energy by mistake, so check your arithmetic and units.

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