A gas at a pressure of 105$Nm^{-2}$expands from 0.6m-3 to 1.2m3 at constant temperature, the work done is

Analyze the question: A gas expands against a constant pressure, and we need the work done. The question text is garbled, so let's read it carefully: the pressure is probably 10⁵ N/m² (written "105"), and the volume goes from 0.6 m³ to 1.2 m³.

Concept: For a gas expanding at constant pressure, work done is

W = P × ΔV = P(V₂ − V₁)

Solution:

• ΔV = 1.2 − 0.6 = 0.6 m³
• If P = 10⁵ N/m²: W = 10⁵ × 0.6 = 6.0 × 10⁴ J

Check on the reading of "105": If the pressure were literally 105 N/m², then W = 105 × 0.6 = 63 J, which is not among the options. So the intended pressure must be 10⁵ N/m², which is also standard atmospheric pressure, a typical value in JAMB questions.

Answer: W = 6.0 × 10⁴ J, which is option D.

Tip: When an exponent is lost in formatting, such as "105" for 10⁵, check which reading gives an answer among the options. Also remember that W = PΔV is the area under a P–V graph. Always compute ΔV first, as final minus initial.