JAMB 2011 Physics · Question 2
An object of mass 2 kg moves with a velocity of 10 ms1 round at circle of radius 4 m. Calculate the centripetal force on the object
Options
- A.25 N
- B.100 N
- C.50 N
- D.40 N
Answer: C. 50 N
Explanation written with AI and checked against the answer key
Analyze the question: An object of mass 2 kg moves at 10 m/s in a circle of radius 4 m. We need the centripetal force.
Concept: The centripetal force is the inward force that keeps an object moving in a circle:
F = mv²/r
where m is mass, v is speed and r is the radius of the circle.
Solution:
- m = 2 kg
- v = 10 m/s
- r = 4 m
F = (2 × 10²) / 4 F = (2 × 100) / 4 F = 200 / 4 F = 50 N
Answer: The centripetal force is 50 N, which is option C.
Tip: Square the velocity before you multiply or divide. Many students compute 2 × 10 = 20 and then square it, or forget to square v at all. If you forget the square, you get 2 × 10 / 4 = 5 N, which is not among the options. Remember "mv² over r" and check your units: kg × m²/s² ÷ m = kg·m/s² = N.
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