JAMB 2010 Physics · Question 13

A car moves with an initial velocity of 25 ms−1^{-1} and reaches a velocity of 45 ms−1^{-1} in 10s. What is the acceleration of the car?

Options

  1. A.2 ms−2ms^{-2}
  2. B.5 ms−2ms^{-2}
  3. C.20 ms−2ms^{-2}
  4. D.25 ms−2ms^{-2}

Answer: A. 2 ms−2ms^{-2}

Explanation written with AI and checked against the answer key

Analyze the question: The car speeds up from 25 m/s to 45 m/s over 10 s. We need its acceleration, which is the rate of change of velocity.

Concept: Acceleration is the change in velocity divided by the time taken:

a = (v − u) / t

where u is the initial velocity, v is the final velocity and t is the time.

Solution:

  • u = 25 m/s
  • v = 45 m/s
  • t = 10 s

a = (45 − 25) / 10 a = 20 / 10 a = 2 m/s²

Answer: The acceleration is 2 ms⁻², which is option A.

Tip: Always subtract the initial velocity from the final velocity before dividing by time. A common mistake is to divide 45 or 25 by 10 directly. Also check your units: m/s divided by s gives m/s².

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