JAMB 2025 Chemistry · Question 104

The process that illustrates reformation of petroleum product is

Options

  1. A.hexene to hexane
  2. B.cyclohexane to benzene
  3. C.hexane to carbon(IV)oxide and water vapour
  4. D.hexane to butane and ethane

Answer: B. cyclohexane to benzene

Explanation written with AI and checked against the answer key

Analyze the question: It asks which process is reforming (reformation) in petroleum refining.

Concept: Petroleum processing includes:

  • Cracking: breaking large hydrocarbon molecules into smaller, more useful ones (e.g., hexane → butane + ethane).
  • Reforming: rearranging the structure of hydrocarbon molecules, without significantly changing the number of carbons, to improve quality (e.g., a higher octane number for petrol). This often involves converting straight-chain alkanes or cycloalkanes into branched alkanes or aromatic compounds, using a catalyst such as platinum.
  • Combustion: burning in oxygen to give CO₂ and water.
  • Hydrogenation: adding H₂ across a double bond (alkene → alkane).

Check each option:

  • A. Hexene to hexane: This adds hydrogen to a double bond, so it is hydrogenation, not reforming.
  • B. Cyclohexane to benzene: C₆H₁₂ → C₆H₆ + 3H₂. The carbon number stays at 6, but the structure is rearranged into an aromatic ring (dehydrogenation). This is a typical catalytic reforming reaction, which is how aromatics are produced to improve petrol quality.
  • C. Hexane to CO₂ and water vapour: This is complete combustion.
  • D. Hexane to butane and ethane: C₆H₁₄ → C₄H₁₀ + C₂H₄ (or similar). A larger molecule breaks into smaller ones, so this is cracking.

Answer: B. Cyclohexane to benzene.

Tip: Remember the key words:

  • Cracking = breaking big molecules into small ones.
  • Reforming = reshaping molecules (same number of carbons, new structure, e.g., cycloalkane → aromatic or straight chain → branched).

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