JAMB 2025 Chemistry · Question 104
The process that illustrates reformation of petroleum product is
Options
- A.hexene to hexane
- B.cyclohexane to benzene
- C.hexane to carbon(IV)oxide and water vapour
- D.hexane to butane and ethane
Answer: B. cyclohexane to benzene
Explanation written with AI and checked against the answer key
Analyze the question: It asks which process is reforming (reformation) in petroleum refining.
Concept: Petroleum processing includes:
- Cracking: breaking large hydrocarbon molecules into smaller, more useful ones (e.g., hexane → butane + ethane).
- Reforming: rearranging the structure of hydrocarbon molecules, without significantly changing the number of carbons, to improve quality (e.g., a higher octane number for petrol). This often involves converting straight-chain alkanes or cycloalkanes into branched alkanes or aromatic compounds, using a catalyst such as platinum.
- Combustion: burning in oxygen to give CO₂ and water.
- Hydrogenation: adding H₂ across a double bond (alkene → alkane).
Check each option:
- A. Hexene to hexane: This adds hydrogen to a double bond, so it is hydrogenation, not reforming.
- B. Cyclohexane to benzene: C₆H₁₂ → C₆H₆ + 3H₂. The carbon number stays at 6, but the structure is rearranged into an aromatic ring (dehydrogenation). This is a typical catalytic reforming reaction, which is how aromatics are produced to improve petrol quality.
- C. Hexane to CO₂ and water vapour: This is complete combustion.
- D. Hexane to butane and ethane: C₆H₁₄ → C₄H₁₀ + C₂H₄ (or similar). A larger molecule breaks into smaller ones, so this is cracking.
Answer: B. Cyclohexane to benzene.
Tip: Remember the key words:
- Cracking = breaking big molecules into small ones.
- Reforming = reshaping molecules (same number of carbons, new structure, e.g., cycloalkane → aromatic or straight chain → branched).
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