JAMB 2025 Chemistry · Question 85

Electron configuration of Chlorine atom is

Options

  1. A.1S2^22S2^22P6^63S2^23P5^5
  2. B.1S2^22S2^22P6^63S2^23P4^4
  3. C.1S2^22S2^22P6^63S2^23P6^6
  4. D.1S2^22S2^22P5^53S2^23P6^6

Answer: A. 1S2^22S2^22P6^63S2^23P5^5

Explanation written with AI and checked against the answer key

Analysis

To find the electron configuration of an atom, we must first determine its atomic number (ZZ). Chlorine (ClCl) is a halogen located in Group 7 of the periodic table, and its atomic number is 17. This means a neutral chlorine atom has 17 electrons that must be arranged in orbitals according to the Aufbau principle.

Concept: The Aufbau Principle

The Aufbau principle states that electrons fill atomic orbitals in order of increasing energy levels. The sequence for filling orbitals is: 1s→2s→2p→3s→3p→4s…1s \rightarrow 2s \rightarrow 2p \rightarrow 3s \rightarrow 3p \rightarrow 4s \dots

Capacity of orbitals:

  • s-orbital: holds a maximum of 2 electrons
  • p-orbital: holds a maximum of 6 electrons
Step-by-Step Solution

We need to distribute 17 electrons into the orbitals following the sequence:

  1. 1s orbital: Fill with 2 electrons (1s21s^2). Remaining: 17−2=1517 - 2 = 15.
  2. 2s orbital: Fill with 2 electrons (2s22s^2). Remaining: 15−2=1315 - 2 = 13.
  3. 2p orbital: Fill with 6 electrons (2p62p^6). Remaining: 13−6=713 - 6 = 7.
  4. 3s orbital: Fill with 2 electrons (3s23s^2). Remaining: 7−2=57 - 2 = 5.
  5. 3p orbital: Place the remaining 5 electrons here (3p53p^5).

Combining these, we get: 1s22s22p63s23p51s^2 2s^2 2p^6 3s^2 3p^5

Verification

Adding the superscripts: 2+2+6+2+5=172 + 2 + 6 + 2 + 5 = 17. This matches the atomic number of Chlorine.

Comparing this to the provided options:

  • Option A: 1s22s22p63s23p51s^2 2s^2 2p^6 3s^2 3p^5 (Matches our calculation)
  • Option B: 1s22s22p63s23p41s^2 2s^2 2p^6 3s^2 3p^4 (Total = 16 electrons)
  • Option C: 1s22s22p63s23p61s^2 2s^2 2p^6 3s^2 3p^6 (Total = 18 electrons, which is Argon)
  • Option D: 1s22s22p53s23p61s^2 2s^2 2p^5 3s^2 3p^6 (Total = 17 electrons, but violates the order of filling)
Exam Tip

Always remember the "2-8-7" shell structure for Chlorine. The 1s21s^2 is the 1st shell (2 electrons), 2s22p62s^2 2p^6 is the 2nd shell (8 electrons), and 3s23p53s^2 3p^5 is the 3rd shell (7 electrons). If you ever forget the long-form configuration, just remember the shell distribution and fill the sub-shells accordingly!

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