JAMB 2025 Chemistry · Question 80

C2_2H5_5OH   +  CH3_3COOH  ⇌  CH3_3COOC2_2H5_5  +  H2_2O The reaction above is

Options

  1. A.condensation
  2. B.fermentation
  3. C.esterification
  4. D.hydrolysis

Answer: C. esterification

Explanation written with AI and checked against the answer key

1. Analyze the question

The question asks you to identify the specific type of chemical reaction occurring between ethanol (C2H5OHC_2H_5OH) and ethanoic acid (CH3COOHCH_3COOH) to produce ethyl ethanoate (CH3COOC2H5CH_3COOC_2H_5) and water (H2OH_2O).

2. Explain the concept

This reaction is a classic example of a reaction between an alcohol and a carboxylic acid.

  • The Principle: When an alcohol reacts with a carboxylic acid in the presence of a strong acid catalyst (usually concentrated H2SO4H_2SO_4), it forms an ester and water. This process is known as esterification.
  • The Equation: R−OH+R′−COOH⇌R′−COOR+H2OR-OH + R'-COOH \rightleftharpoons R'-COOR + H_2O In this specific case: • C2H5OHC_2H_5OH (Ethanol) + CH3COOHCH_3COOH (Ethanoic acid) ⇌\rightleftharpoons CH3COOC2H5CH_3COOC_2H_5 (Ethyl ethanoate) + H2OH_2O (Water).
3. Show the solution
  • Step 1: Identify the reactants. We have an alcohol (C2H5OHC_2H_5OH) and an organic acid (CH3COOHCH_3COOH).
  • Step 2: Identify the products. The product CH3COOC2H5CH_3COOC_2H_5 is an ester (specifically ethyl ethanoate), and water is produced as a byproduct.
  • Step 3: Match the reaction type. Since the reaction produces an ester from an alcohol and an acid, it is defined as esterification.
4. Identify the answer
  • A (Condensation): While esterification is a type of condensation reaction (because a small molecule like water is removed), "esterification" is the more specific and accurate term for this reaction in chemistry.
  • B (Fermentation): This is the process of breaking down sugars into alcohol and CO2CO_2 using enzymes.
  • C (Esterification): This is the correct term for the formation of an ester from an alcohol and an acid.
  • D (Hydrolysis): This is the reverse of esterification (breaking an ester down using water).
5. Tip

Memory Trick: Think of the name "Ester-ification" as "making an Ester." Whenever you see an alcohol and a carboxylic acid on the left side of the arrow, look for the ester functional group (−COOC−-COOC-) on the right side. If you see it, the answer is almost certainly esterification!

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