JAMB 2024 Chemistry · Question 41

92238^{238}_{92}U  + 01^1_0n → 92239^{239}_{92}U  The process above produces

Options

  1. A.atomic mutation
  2. B.a radioactive isotope
  3. C.other neutrons
  4. D.radiations

Answer: B. a radioactive isotope

Explanation written with AI and checked against the answer key

1. Analyze the Question

The reaction provided is: 92238U+01n→92239U^{238}_{92}\text{U} + ^{1}_{0}\text{n} \rightarrow ^{239}_{92}\text{U}

We are looking at a nuclear reaction where a Uranium-238 nucleus captures a neutron to become Uranium-239. We need to identify the nature of the product formed.

2. Explain the Concept
  • Isotopes: These are atoms of the same element (same atomic number) that have different mass numbers due to a different number of neutrons.
  • Radioactivity: Many heavy isotopes, especially those created by neutron bombardment (like 239U^{239}\text{U}), are unstable. Because they have an excess of neutrons, they are inherently radioactive; they will eventually undergo radioactive decay (usually beta decay) to become more stable.
  • Nuclear Transmutation: This is the conversion of one chemical element or isotope into another. While this is a transmutation, the specific characteristic of the product 239U^{239}\text{U} is that it is an unstable, radioactive isotope.
3. Show the Solution
  • Step 1: Observe the atomic number (bottom number). It remains 92, meaning the element is still Uranium.
  • Step 2: Observe the mass number (top number). It increases from 238 to 239.
  • Step 3: Recognize that 239U^{239}\text{U} is an isotope of 238U^{238}\text{U}.
  • Step 4: In nuclear chemistry, when a heavy nucleus captures a neutron, the resulting isotope is almost always unstable and undergoes radioactive decay. Therefore, the product is classified as a radioactive isotope.
4. Identify the Answer
  • A (Atomic mutation): This is a vague term not typically used to describe this specific outcome.
  • B (A radioactive isotope): This is correct. 239U^{239}\text{U} is an isotope of Uranium, and it is radioactive.
  • C (Other neutrons): No additional neutrons are released in this specific equation.
  • D (Radiations): While the isotope will eventually emit radiation, the product itself is the isotope, not the radiation.
5. Exam Tip

Whenever you see a nuclear equation where a neutron (01n^{1}_{0}\text{n}) is added to a nucleus, the product is almost always a heavier isotope of the original element. Because these "neutron-rich" isotopes are unstable, they are almost always radioactive. Remember: Neutron capture = Radioactive isotope formation.

AI can make mistakes. Report anything that looks wrong.

Past questions © the examination body (JAMB/WAEC/NECO). DeeepSolve is not affiliated with them. Rights holders: see /copyright.