JAMB 2023 Chemistry · Question 12
What is Faraday's constant?
Options
- A.6.022 x 10 mol
- B.3.00 x 10 m/s
- C.9.81 m/s
- D.96,485 C/mol
Answer: D. 96,485 C/mol
Explanation written with AI and checked against the answer key
Analyze the question: You are asked for the value of Faraday's constant. Each option is a different physical constant, so you only need to match each one to its name.
Explain the concept: Faraday's constant (F) is the magnitude of electric charge carried by one mole of electrons. It links the amount of substance deposited or liberated in electrolysis to the charge passed.
F = N_A × e = (6.022 × 10²³ mol⁻¹) × (1.602 × 10⁻¹⁹ C) ≈ 96,485 C/mol
In Nigerian exams you will often see it rounded to 96,500 C/mol.
Check each option:
- A. 6.022 × 10²³ mol⁻¹: This is Avogadro's constant, the number of particles in one mole.
- B. 3.00 × 10⁸ m/s: This is the speed of light in a vacuum.
- C. 9.81 m/s²: This is the acceleration due to gravity (g).
- D. 96,485 C/mol: This is Faraday's constant, the charge on one mole of electrons.
Why it matters (quick application): Faraday's first law of electrolysis says mass deposited = (Q × M) / (n × F), where Q = I × t. For example, to deposit 1 mole of Cu from Cu²⁺ (n = 2), you need 2 × 96,500 = 193,000 C.
Exam tip: Look at the unit. C/mol means charge per mole, which only Faraday's constant has. Also remember the link F = N_A × e, which helps you tell Avogadro's number and Faraday's constant apart.
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