JAMB 2019 Chemistry · Question 2
The two ions responsible for hardness in water are
Options
- A.Ca and / or Mg
- B.K and / or Mg
- C.Ca and / or Li
- D.Ca and / or Na
Answer: A. Ca and / or Mg
Explanation written with AI and checked against the answer key
Step 1: Analyze the question The question asks which two ions cause hardness in water.
Step 2: Concept Hard water is water that does not easily form lather with soap. Hardness is caused by dissolved salts of calcium and magnesium, which are present as Ca²⁺ and Mg²⁺ ions.
- Temporary hardness is caused by calcium or magnesium hydrogencarbonates, Ca(HCO₃)₂ and Mg(HCO₃)₂. It can be removed by boiling.
- Permanent hardness is caused by calcium or magnesium sulphates and chlorides, CaSO₄, MgSO₄, CaCl₂ and MgCl₂. It needs a chemical method such as adding washing soda (Na₂CO₃) or ion exchange.
Why soap fails to lather: Soap is sodium stearate, C₁₇H₃₅COONa. Ca²⁺ and Mg²⁺ react with it to form an insoluble precipitate called scum:
Ca²⁺(aq) + 2C₁₇H₃₅COO⁻(aq) → Ca(C₁₇H₃₅COO)₂(s)
Soap is wasted until all the Ca²⁺ and Mg²⁺ have been precipitated, and only then does lather form.
Step 3: Eliminate the options
- B (K⁺ and Mg²⁺): K⁺ does not cause hardness. Its soaps are soluble.
- C (Ca²⁺ and Li⁺): Li⁺ does not cause hardness.
- D (Ca²⁺ and Na⁺): Na⁺ soaps are the soluble soaps themselves, so Na⁺ does not cause hardness.
- A (Ca²⁺ and/or Mg²⁺) is correct.
Step 4: Answer
Exam tip: Remember that hardness comes from "Ca and Mg", the two metals that form insoluble soaps. Group 1 ions (Na⁺, K⁺, Li⁺) never cause hardness because their soaps are soluble.
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