The IUPAC name of the compound CF$_3$CHBrCl is

Analyze the question: CF₃CHBrCl is halothane, a two-carbon (ethane) chain carrying four halogen substituents. We need the correct IUPAC name, which depends on numbering and alphabetical order.

Concept: For substituted alkanes:

1. Choose the longest chain (here 2 carbons, so ethane).
2. Number the chain so the substituents get the lowest set of locants.
3. List substituents in alphabetical order (ignoring the prefixes di-, tri-, etc.).

Solution:

• Carbon A: CF₃ (3 fluorines)
• Carbon B: CHBrCl (1 bromine, 1 chlorine)

Numbering options:

• Option 1: CF₃ is C1, so the locants are {1,1,1,2,2} (F at 1,1,1; Br at 2; Cl at 2).
• Option 2: CHBrCl is C1, so the locants are {1,1,2,2,2}.

Compare the sets at the first point of difference: {1,1,1,2,2} is lower than {1,1,2,2,2}. So CF₃ is C1.

Alphabetical order: bromo (b), chloro (c), fluoro (f). The prefix "tri" in trifluoro is ignored, so fluoro is sorted under "f".

Name: 2-bromo-2-chloro-1,1,1-trifluoroethane

Checking the options:

• A: chloro listed before bromo, so the alphabetical order is wrong.
• B: correct numbering and correct alphabetical order. ✔
• C: numbering gives the higher locant set {1,1,2,2,2}, so it is wrong.
• D: right locants but not in alphabetical order (fluoro is listed first).

Answer: B

Tip: When naming haloalkanes, do two checks. First, find the lowest locant set (all substituents together). Second, write the prefixes alphabetically. The multipliers (di, tri, tetra) never count for alphabetizing.