JAMB 2018 Chemistry · Question 46

The salt that reacts with dilute hydrochloric acid to produce a pungent smelling gas which decolourizes…

Question

The salt that reacts with dilute hydrochloric acid to produce a pungent smelling gas which decolourizes acidified purple potassium tetraoxomanganate (VII) solution is

  1. A.Na2_2SO4_4
  2. B.Na2_2SO3_3
  3. C.Na2_2S
  4. D.Na2_2CO3_3

Answer: B. Na2_2SO3_3

Explanation written with AI and checked against the answer key

Analysis

To solve this question, we need to identify which of the given salts reacts with dilute hydrochloric acid (HCl) to produce a gas that:

  1. Has a pungent smell.
  2. Decolourizes acidified purple potassium tetraoxomanganate (VII) (KMnO4KMnO_4).
Concept Explanation
  • Na2_2SO4_4 (Sodium tetraoxosulphate VI): Does not react with dilute HCl to produce a gas.
  • Na2_2SO3_3 (Sodium trioxosulphate IV): Reacts with dilute HCl to produce sulphur (IV) oxide (SO2SO_2) gas. SO2SO_2 is a colourless gas with a characteristic pungent, choking smell (like burnt matches). It acts as a reducing agent, which causes the purple KMnO4KMnO_4 to turn colourless.
  • Na2_2S (Sodium sulphide): Reacts with dilute HCl to produce hydrogen sulphide (H2SH_2S) gas. While H2SH_2S has a smell, it smells like rotten eggs, not a pungent choking smell, and it produces a yellow precipitate of sulphur when reacting with KMnO4KMnO_4.
  • Na2_2CO3_3 (Sodium trioxocarbonate IV): Reacts with dilute HCl to produce carbon (IV) oxide (CO2CO_2). CO2CO_2 is odourless and does not decolourize acidified KMnO4KMnO_4.
Step-by-Step Solution
  1. Reaction: When sodium trioxosulphate (IV) reacts with hydrochloric acid: $Na2SO3(s)+2HCl(aq)→2NaCl(aq)+H2O(l)+SO2(g)Na_2SO_3(s) + 2HCl(aq) \rightarrow 2NaCl(aq) + H_2O(l) + SO_2(g)$
  2. Gas Identification: The gas produced is SO2SO_2.
  3. Chemical Test: SO2SO_2 is a strong reducing agent. When bubbled through acidified KMnO4KMnO_4, it reduces the manganese from the +7 oxidation state (purple) to the +2 oxidation state (colourless): $5SO2+2MnO4−+2H2O→5SO42−+2Mn2++4H+5SO_2 + 2MnO_4^- + 2H_2O \rightarrow 5SO_4^{2-} + 2Mn^{2+} + 4H^+$ This confirms the decolourisation process.
Conclusion

The salt that satisfies both conditions (pungent smell and decolourisation of KMnO4KMnO_4) is sodium trioxosulphate (IV).

Exam Tip

Whenever you see "decolourizes acidified KMnO4KMnO_4," immediately think of reducing agents. Common reducing agents in your syllabus include SO2SO_2, H2SH_2S, and Fe2+Fe^{2+} salts. If the question mentions a "pungent smell," SO2SO_2 is almost always the intended answer!

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