JAMB 2018 Chemistry · Question 7

Suitable reagents for the laboratory preparation of nitrogen are

Options

  1. A.sodium dioxonitrate(III) and ammonium chloride
  2. B.sodium trioxonitrate(V) and ammonium chloride
  3. C.sodium chloride and ammonium trioxonitrate(V)
  4. D.sodium chloride and ammonium di-ozonitrate(III)

Answer: A. sodium dioxonitrate(III) and ammonium chloride

Explanation written with AI and checked against the answer key

Analyze the question: We need the pair of reagents used in the laboratory to prepare nitrogen gas.

Concept: The standard laboratory preparation of nitrogen involves heating a solution of ammonium nitrite, which decomposes to give nitrogen and water. Ammonium nitrite is unstable and is not stored, so it is made in the flask by mixing:

  • sodium nitrite, NaNO₂ (sodium dioxonitrate(III))
  • ammonium chloride, NH₄Cl

Solution:

  1. Double decomposition forms ammonium nitrite: NaNO₂(aq) + NH₄Cl(aq) → NH₄NO₂(aq) + NaCl(aq)
  1. Gentle heating decomposes the ammonium nitrite: NH₄NO₂(aq) → N₂(g) + 2H₂O(l)

Checking the options:

  • A. Sodium dioxonitrate(III) (NaNO₂) with ammonium chloride (NH₄Cl) gives NH₄NO₂, then N₂. This is correct.
  • B. Sodium trioxonitrate(V) is NaNO₃, a nitrate. Combined with NH₄Cl, it would give ammonium nitrate, which decomposes to N₂O (laughing gas), not N₂.
  • C. NaCl with NH₄NO₃ gives no suitable reaction for nitrogen. Heating NH₄NO₃ gives N₂O.
  • D. NaCl with ammonium nitrite would work only if the ammonium nitrite were available as a reagent. It is unstable and not a standard bench reagent, and the pairing is not the standard method. Option A is the standard choice.

Answer: A.

Exam tip: Remember the oxidation-state naming: dioxonitrate(III) is nitrite (NO₂⁻) and trioxonitrate(V) is nitrate (NO₃⁻). For nitrogen gas, think "nitrite + ammonium", because ammonium nitrite breaks down to N₂ + 2H₂O. Ammonium nitrate gives N₂O instead.

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