JAMB 2018 Chemistry · Question 7
Suitable reagents for the laboratory preparation of nitrogen are
Options
- A.sodium dioxonitrate(III) and ammonium chloride
- B.sodium trioxonitrate(V) and ammonium chloride
- C.sodium chloride and ammonium trioxonitrate(V)
- D.sodium chloride and ammonium di-ozonitrate(III)
Answer: A. sodium dioxonitrate(III) and ammonium chloride
Explanation written with AI and checked against the answer key
Analyze the question: We need the pair of reagents used in the laboratory to prepare nitrogen gas.
Concept: The standard laboratory preparation of nitrogen involves heating a solution of ammonium nitrite, which decomposes to give nitrogen and water. Ammonium nitrite is unstable and is not stored, so it is made in the flask by mixing:
- sodium nitrite, NaNO₂ (sodium dioxonitrate(III))
- ammonium chloride, NH₄Cl
Solution:
- Double decomposition forms ammonium nitrite: NaNO₂(aq) + NH₄Cl(aq) → NH₄NO₂(aq) + NaCl(aq)
- Gentle heating decomposes the ammonium nitrite: NH₄NO₂(aq) → N₂(g) + 2H₂O(l)
Checking the options:
- A. Sodium dioxonitrate(III) (NaNO₂) with ammonium chloride (NH₄Cl) gives NH₄NO₂, then N₂. This is correct.
- B. Sodium trioxonitrate(V) is NaNO₃, a nitrate. Combined with NH₄Cl, it would give ammonium nitrate, which decomposes to N₂O (laughing gas), not N₂.
- C. NaCl with NH₄NO₃ gives no suitable reaction for nitrogen. Heating NH₄NO₃ gives N₂O.
- D. NaCl with ammonium nitrite would work only if the ammonium nitrite were available as a reagent. It is unstable and not a standard bench reagent, and the pairing is not the standard method. Option A is the standard choice.
Answer: A.
Exam tip: Remember the oxidation-state naming: dioxonitrate(III) is nitrite (NO₂⁻) and trioxonitrate(V) is nitrate (NO₃⁻). For nitrogen gas, think "nitrite + ammonium", because ammonium nitrite breaks down to N₂ + 2H₂O. Ammonium nitrate gives N₂O instead.
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