JAMB 2014 Chemistry · Question 35
A silicon -containing ore has 92% 28Si, 5% 29Si and 3% 30Si. Calculate the relative atomic mass of the silicon.
Options
- A.14.00
- B.29.00
- C.28.11
- D.28.00
Answer: C. 28.11
Explanation written with AI and checked against the answer key
Analyze the question: You're given the isotopes of silicon and their percentage abundances. The relative atomic mass is the weighted average of the isotopic masses.
Concept:
Relative atomic mass = Σ (isotopic mass × % abundance) ÷ 100
Solution:
- ²⁸Si: 28 × 92 = 2576
- ²⁹Si: 29 × 5 = 145
- ³⁰Si: 30 × 3 = 90
Total = 2576 + 145 + 90 = 2811
Relative atomic mass = 2811 ÷ 100 = 28.11
Check: The answer should be close to 28, since most of the sample (92%) is ²⁸Si, and slightly above it because of the heavier isotopes. 28.11 fits this.
Answer: C. 28.11
Tip: Start from the lightest isotope and add only the "extra" mass: 28 + (5 × 1 + 3 × 2)/100 = 28 + 11/100 = 28.11. This saves you from multiplying large numbers in the exam hall.
AI can make mistakes. Report anything that looks wrong.
Past questions © the examination body (JAMB/WAEC/NECO). DeeepSolve is not affiliated with them. Rights holders: see /copyright.
