JAMB 2012 Chemistry · Question 24
If the elements X and Y have atomic numbers 11 and 17 respectively, what type of bond can they form?
Options
- A.Dative
- B.Covalent
- C.Ionic
- D.Metallic
Answer: C. Ionic
Explanation written with AI and checked against the answer key
Step 1: Analyze the question We are given two elements by atomic number and asked what bond they form together.
Step 2: Find the electronic configurations
- X (atomic number 11): 2, 8, 1. This is sodium (Na), a metal with 1 valence electron.
- Y (atomic number 17): 2, 8, 7. This is chlorine (Cl), a non-metal with 7 valence electrons.
Step 3: Apply the concept
- A metal and a non-metal usually combine by electron transfer, which gives an ionic (electrovalent) bond.
- Non-metals bonding with non-metals share electrons, which gives a covalent bond.
- A dative bond needs one atom to supply both electrons of the shared pair (as in NH₄⁺).
- A metallic bond occurs between metal atoms only.
Step 4: Solution
- Na loses its 1 valence electron: Na → Na⁺ + e⁻ (now 2, 8, like neon).
- Cl gains that electron: Cl + e⁻ → Cl⁻ (now 2, 8, 8, like argon).
- The oppositely charged ions, Na⁺ and Cl⁻, attract each other strongly. This forms sodium chloride, NaCl, held together by an ionic bond.
Answer: C. Ionic
Tip: For bond-type questions, first identify the elements from their atomic numbers. A metal (Groups 1, 2, 3) plus a non-metal (Groups 6, 7) gives ionic. Two non-metals give covalent. Remember "Metal + Non-metal = Ionic".
AI can make mistakes. Report anything that looks wrong.
Past questions © the examination body (JAMB/WAEC/NECO). DeeepSolve is not affiliated with them. Rights holders: see /copyright.
