JAMB 2018 Biology · Question 7
The overall reaction in glycolysis can be summarised as
Options
- A.CHO -----> CHO + 4H + ATP
- B.CHO -----> 2CHO + 4H + 2ATP
- C.CHO -----> 2CHO + 4H + ADP
- D.CHO -----> 2CHO + 4H + 2ADP
Answer: B. CHO -----> 2CHO + 4H + 2ATP
Explanation written with AI and checked against the answer key
Analyze the question: It asks for the balanced summary equation of glycolysis, the first stage of respiration, which takes place in the cytoplasm.
Concept: Glycolysis breaks down one molecule of glucose (6C) into two molecules of pyruvic acid (3C each, C₃H₄O₃). Along the way:
- 2 ATP are used up in the early (investment) phase.
- 4 ATP are made in the later (pay-off) phase, so the net gain is 2 ATP.
- 2 NAD⁺ are reduced to 2 NADH, which is the same as 4 hydrogen atoms (4H) removed.
Step-by-step check:
- Carbon balance: 6C on the left. Two pyruvate molecules give 2 × 3 = 6C. So we need 2C₃H₄O₃, not one. This eliminates A.
- Hydrogen removed: 4H are released (taken up by NAD⁺). This is in all the remaining options.
- Energy: glycolysis gives a net gain of 2 ATP. ATP is the product, not ADP. ADP is a reactant that gets converted to ATP. This eliminates C and D, which show ADP as a product.
Overall equation:
C₆H₁₂O₆ → 2C₃H₄O₃ + 4H + 2ATP
Tip: Remember the "2-2-2 rule" for glycolysis: 1 glucose gives 2 pyruvate, a net of 2 ATP, and 2 NADH (4H). Also, ATP is always the energy product, so if you see ADP on the product side, the option is wrong.
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